In an ap sum of first n terms is 3n 2/2
WebApr 3, 2024 · We will use the formula of sum of n terms of an AP given by the relation S n = n 2 [ 2 a + ( n − 1) d], where a is the first term and d is the common difference. We will assume variables for the first term and the common differences of the AP’s. We will then compare the ratio of the formula to the given ratio. WebApr 6, 2024 · We are given that, sum of the first 3n terms is equal to the sum of the next n terms. Sum of 3n terms of AP = S 3 n = using above formula, we get: S 3 n = 3 n 2 [ 2 a + ( 3 n − 1) d] Next n term is given by 3n + n = 4n Then, according to condition of question, we have: S 3 n = S 4 n − S 3 n ⇒ 2 S 3 n = S 4 n
In an ap sum of first n terms is 3n 2/2
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WebThe formula for finding the n-th term of an AP is: an = a + (n − 1) × d Where a = First term d = Common difference n = number of terms a n = nth term Example: Find the nth term of AP: 1, 2, 3, 4, 5…., an, if the number of terms are 15. Solution: Given, AP: 1, 2, 3, 4, 5…., an n=15 By the formula we know, a n = a+ (n-1)d First-term, a =1 WebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression …
WebMar 30, 2024 · There are 2 AP s with different first term and common difference For the first AP Let first term be a common difference be d Sum of n term = Sn = /2 (2a + (n 1)d) & nth term = an = a + (n 1)d Similarly for second AP Let first term = A common difference = D Sn = /2 (2A + (n 1)D) & nth term = An = A + (n 1)D We need to find ratio of 12th term i.e. … WebAug 9, 2024 · It is an arithmetic progression with first term as 5 and common difference as 6 and 20^(th) term is 119 As sum of n terms of a certain series is given by S_n=2n+3n^2, Sum of 20 terms is 2×20+3×20^2=40+1200=1240. Further, sum of 19 terms is 2×19+3×19^2=38+1083=1121,. Hence 20^(th) term is 1240-1121=119. As sum of 1 term …
WebIn an A.P., the sum of first n terms is 3n2 2 + 13 2n. Find its 25th term. Solution n term sum = 3n²/2 + 13n/2 as we know that nth term = (Sum of nth term ) - ( sum of (n-1)th term) … WebApr 15, 2024 · The sum of the first n terms of an AP is given by Sn = (3n2 – n). Find its (i) nth term, (ii) first term and (iii) common difference. arithmetic progression class-10 1 Answer +1 vote answered Apr 15, 2024 by Nidhi01 (60.1k points) selected Apr 16, 2024 by Vevek01 Best answer Sn = 3n2 – n S1 = 3 (1)2 – 1 = 3 – 1 = 2 S2 = 3 (2)2 – 2 = 12 – 2 = 10
Web(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55.
WebIn an AP the sum of first n terms is n/2(3n+5) find the 25th term of the AP CBSE Class 10 Maths#Kcpsir#Class10Mathsclass 10 maths 2024 paper solutionCBSE ... greek financial crisis 2016WebIf the sum of the first n terms of an A.P. is (1/2) [3n2 + 7n], then find its nth term. Hence write its 20th term. arithmetic progression cbse class-10 1 Answer +4 votes answered Sep 30, 2024 by KajalAgarwal (45.2k points) selected Oct 1, 2024 by Vikash Kumar Hence, a2 = 62 ← Prev Question Next Question → Find MCQs & Mock Test greek financial crisis explained bbcWebIn an A.P the sum of first n terms is 3n2/2 + 13n/2. Find the 25th term arithmetic progression cbse class-10 1 Answer +1 vote answered Sep 30, 2024 by KajalAgarwal … greek financial crisis summaryWebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 … greek financial crisis overviewWebThe sum of the first term alone is 3 ⋅ 1 + 2 ⋅ 1 2 = 5. So the first term is 5. The sum of the first two terms is 3 ⋅ 2 + 2 ⋅ 2 2 = 14, so the second term is 14 − 5 = 9. The sum of the first … greek financial crisis wikiWebAnswer (1 of 3): Sum of the first n terms, Sₙ= 5n²-2n Let S₄₉ and S₅₀ be the sum of first 49 terms and first 50 terms respectively. Let t₅₀ be the 50 th term. S₅₀= S₄₉+t₅₀ t₅₀= S₅₀-S₄₉ S₄₉ = 5(49)²-2(49) = 11907 S₅₀ = 5(50)²-2(50) = 12400 t₅₀ = … flow by mawWebTo find the sum of the first n terms of an arithmetic sequence use the formula, S n = n ( a 1 + a 2) 2 , where n is the number of terms, a 1 is the first term and a n is the last term. Example 1: Find the sum of the first 20 terms of the arithmetic series if a 1 = 5 and a 20 = 62 . S 20 = 20 ( 5 + 62) 2 S 20 = 670 Example 2: greek financial crisis explained youtube